(-3k-2)^2/2b-4y^-1

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Solution for (-3k-2)^2/2b-4y^-1 equation: 


x in (-oo:+oo)

b*(((-3*k-2)^2)/2)-(4*y^-1) = 0

b*(((-3*k-2)^2)/2)-4*y^-1 = 0

(b*(-3*k-2)^2)/2-4/y = 0

(b*y*(-3*k-2)^2)/(2*y)+(-4*2)/(2*y) = 0

b*y*(-3*k-2)^2-4*2 = 0

9*b*k^2*y+12*b*k*y+4*b*y-8 = 0

(9*b*k^2*y+12*b*k*y+4*b*y-8)/(2*y) = 0

(9*b*k^2*y+12*b*k*y+4*b*y-8)/(2*y) = 0 // * 2*y

9*b*k^2*y+12*b*k*y+4*b*y-8 = 0

x belongs to the empty set

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